/* CHECK.C - Compute parity checks and other stats on decodings. */ /* Copyright (c) 2001 by Radford M. Neal * * Permission is granted for anyone to copy, use, modify, or distribute this * program and accompanying programs and documents for any purpose, provided * this copyright notice is retained and prominently displayed, along with * a note saying that the original programs are available from Radford Neal's * web page, and note is made of any changes made to the programs. The * programs and documents are distributed without any warranty, express or * implied. As the programs were written for research purposes only, they have * not been tested to the degree that would be advisable in any important * application. All use of these programs is entirely at the user's own risk. */ #include #include #include #include "mod2sparse.h" #include "check.h" /* COMPUTE PARITY CHECKS. Returns the number of parity checks violated by dblk. The results of all the parity checks are stored in pchk. */ int check ( mod2sparse *H, /* Parity check matrix */ char *dblk, /* Guess for codeword */ char *pchk /* Place to store parity checks */ ) { int M, i, c; M = mod2sparse_rows(H); mod2sparse_mulvec (H, dblk, pchk); c = 0; for (i = 0; i1); } return changed; } /* COMPUTE THE EXPECTED NUMBER OF PARITY CHECK ERRORS. Computes the expected number of parity check errors with respect to the distribution given by the bit probabilities passed, with bits assumed to be independent. */ double expected_parity_errors ( mod2sparse *H, /* Parity check matrix */ double *bpr /* Bit probabilities */ ) { mod2entry *f; double ee, p; int M, i, j; M = mod2sparse_rows(H); ee = 0; for (i = 0; i0) { ll -= bpr[j]*log(1+1/lratio[j]); } if (bpr[j]<1) { ll -= (1-bpr[j])*log(1+lratio[j]); } } return ll; } /* COMPUTE ENTROPY FROM BIT PROBABILITIES. Computes the entropy of the distribution given by the bit probabilities, on the assumption that bits are independent. */ double entropy ( double *bpr, /* Bit probabilities */ int N /* Length of codeword */ ) { double e; int j; e = 0; for (j = 0; j0 && bpr[j]<1) { e -= bpr[j]*log(bpr[j]) + (1-bpr[j])*log(1-bpr[j]); } } return e/log(2.0); }